Question

which term pf the AP 8, 14, 20........ will be 72 more than ots 41st term?

Answer 1

Heya !!!

AP = 8 , 14 , 20......

Here,

First term (A) = 8

Common Difference (D) = 14-8 = 6

Therefore,

41st term is given by

T41 = A + 40D

= 8 + 40 × 6 = 8 + 240 = 248

Required term = ( 248 + 72) = 312

Let nth term of the given AP will be 72 more than it's 41st term.

Then,

Tn = 312

A + ( N -1) × D = 320

8 + ( N -1) × 6 = 320

6N - 6 + 8 = 320

6N = 320-2

N =318/6

N = 53

Hence,

53th term of the given AP will be 72 more than it's 41st term.

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Answer 2

a = 8 , d = 6
Let Tn term of an AP will be 72 more than 41st term.

Tn = 72 + 41st term
a + (n - 1)d = 72 + (a + 40d)
8 + (n - 1)6 = 72 + (8 + 40*6)
8 + 6n - 6 = 72 + 248
2 + 6n = 320
6n = 318
n = 53

51st term of an AP will be 72 more than 41st term.