Question

which term the sequence -1,3,7,11.... is 95.

Answer 1

a= -1
a(nth term) =95
Solving,
a+d=3 
a= -1
----
d=4
a(n)=a+(n-1)d
95= -1+[n-1][4]
96/4+1=n
n=25

Answer 2

The number of term the sequence  is 25.

Step-by-step explanation:

The given sequence are:

-1, 3, 7, 11....

Here, first term(a) = - 1, common difference(d) = 3 - (- 1) = 4 and $a_{n}=95$

To find, the number of term the sequence = ?

Let the number of term = n

We know that,

$a_{n} =a+(n-1)d$

⇒$-1+(n-1)4=95$

⇒ $(n-1)4=95+1=96$

⇒$n-1=\dfrac{96}{4} =24$

⇒ $n=24+1=25$

Hence, the number of term the sequence  is 25.