Question

which the term of the A.P : 5,10,15,....will be 130 more than its 31st term?
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Answer 1

Answer:

44

Step-by-step explanation:

First term, A=5 ;Common difference, d=10 ;

31st term = a + (n-1)d

= 5+ 30×10

=305

Then 130 more than 31st term

= 305+130= 435

So let nth term is 435

Then, 5+(n-1)10 = 435

n-1 = 43

n = 44 is the required answer.....

hope it will help u..