Which three consecutive numbers when added together equal 21?
Answers
Answered by
2
6, 7 and 8
Let the first number be n
n
+
(
n
+
1
)
+
(
n
+
2
)
=
21
simplifies to
3
n
=
18
divide by 3 gives
n
=
6
,
(
n
+
1
)
=
7
and
(
n
+
2
)
=
8
Answered by
5
It is given that their sum is 21.
So,
x + (x+2) + (x+4) = 21
= 3x + 6 = 21
= 3x = 15
x = 5
and x+2 = 7
x+4 = 9.
Hence, the three consecutive odd numbers whose sum is 21 are 5, 7 and 9.
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