Question

which tomb of the AP -1 , 3, 7, 11......... is 99? (answer:- -25)​

Answer 1

Answer:

Step-by-step explanation:

here a= -1

d= 3-(-1)=3+1=4

$a_{n}$= -1 + (n-1)4= 99

= (n-1)4=99+1= 100

= n-1=100/4= 25

= n=1+25 = 26

so the 26 th term of the AP will be 99

Answer 2

Step-by-step explanation:

here a= -1

d= 3-(-1)=3+1=4

a_{n}a

n

= -1 + (n-1)4= 99

= (n-1)4=99+1= 100

= n-1=100/4= 25

= n=1+25 = 26

so the 26 th term of the AP will be 99