Which transition of Li^+2 is associated with same energy as n=6 To n=4 transition in He^+
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Answer:
transition from n=9 to n=6
Explanation:
Energy of nth orbit = -2.18*10^-18 *n^2/z^2 so E of He+ in n=6 = -2.18*10^-18*2^2/6^2 =-2.18*10^-18/9 this equation 1 then for Li3+ E =-2.18*19^-18*3^2/n^2 this is equation 2 now equates these two equation -2.18*10^-18/9=-2.18*10^-18*9/n^2=> n^2=9*9=81 => n=9 same as He+ in n=4 we get Li3+ in n=6 so transition from n=9 to n=6
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