Question

Which transmission in the hydrogen spectrum have the same wavelength as balmer trasntion n=4 to n=2?

Answer 1

Answer:

Karen ka va tr a

r u the same

Answer 2

For H-like particles, ṽ = (2π2mZ2e4/ch3)×(1/n12 – 1/n22) = RZ2(1/n12 – 1/n22)

∴ For He+ spectrum, Balmer transition, n=4 to n=2

ṽ = 1/λ = RZ2(1/22 – 1/42) = R×4×3/16 = 3R/4

For hydrogen spectrum ,

ṽ = 1/λ = R(1/n12 – 1/n22) = 3R/4 ⇒ (1/n12 – 1/n22) = 3/4

which can be true only for n1=1 and n2=2 i.e. transition from n=2 to n=1.