Question

which trem of A.P 7,4,1,.....is -56
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Answer 1

Answer:

let the last term of an AP be 140

therefore an=140

an=a+(n-1)(d)

140=(-7)+(n-1)(3)

140=(-7)+3n-3

-7-3+3n=140

3n-10=140

3n=150

n=150/3

n=50

therefore we can say that 140 is from of the given arthematic progression

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