Question

Which two consecutive integers 3 in to the square root of 100 lies

Answer 1

Answer:

The square root of 120 must lie between 10 and 11, as:

1.   For every Real x if x>1 then x^2>1

 2.  10^2=100 so 10 < Sqrt(120)

  3. 11^2=121 so 11 > Sqrt(120),

   Therefore Sqrt(120) is greater than 10 and less than 11 so it lies between the two.

Please note that Mathematically strict proof requires apparatus of Real Analysis - one must define greater than and less than operators before usin them, etc…

Step-by-step explanation:

Answer 2

Answer:

The square root of 3 lies between 1 and 2.