Question

which two digit number is equal to twice the sum
of its digits ?​

Answer 1

Answer:

answer is 18 hope this helps..

Answer 2

The two-digit number which is equal to twice the sum of its digits is 18.

Given,

A 2-digit number is twice the sum of its digits.

To find,

The number.

Solution,

It is given here that a number having two digits is twice the sum of its digits.

Firstly, let the number be $xy$ such that $x$ is the ten's digit and $y$ is the unit's digit of the number.

Now, the number can be written as $10x+y.$

According to the given condition, this number $10x+y$ should be equal to twice the sum of $x$ and $y.$ This can be expressed as,

$10x+y=2(x+y) \hfill ...(1)$

Solving the above equation (1),

$10x+y=2x+2y$

Rearranging and simplifying,

$10x-2x=2y-y$

$\implies 8x=y \hfill ...(2)$

Now, it can be observed that the above equation (2) can only be satisfied only when $x=1,$ and $y=8.$

Thus, the number is

$10x+y$

$=10(1)+(8)=10+8=18.$

Therefore, the two-digit number which is equal to twice the sum of its digits is 18.

#SPJ6