Which two digit numbers when added to 27 get reversed
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Let our number is 10x + y , As x is tens place digit and y is ones .
So, from given condition , we get
10x + y + 27 = 10y + x
9x - 9y = - 27
x - y = - 3
So , here we can have different value of x andy , As :
1 - 4 = -3
Or
2 - 5 = - 3
Or
3 - 6 = - 3
Or
4 - 7 = - 3
Or
5 - 8 = - 3
Or
6 - 9 = - 3
So, we can have these two digit numbers , As :
we take x = 1 and y 4 , So
14 + 27 = 41
Or
we take x = 2 and y 5, So
25 + 27 = 52
Or
we take x = 3 and y 6 , So
36 + 27 = 63
Or
we take x = 4 and y 7 , So
47 + 27 = 74
Or
we take x = 5 and y 8 , So
58 + 27 = 85
Or
we take x = 6 and y 9 , So
69 + 27 = 96
So,
we can say two digit numbers ( 14 , 25 , 36 , 47 , 58 , 69 ) when added to 27 get reversed.
HOPE IT HELPS....
So, from given condition , we get
10x + y + 27 = 10y + x
9x - 9y = - 27
x - y = - 3
So , here we can have different value of x andy , As :
1 - 4 = -3
Or
2 - 5 = - 3
Or
3 - 6 = - 3
Or
4 - 7 = - 3
Or
5 - 8 = - 3
Or
6 - 9 = - 3
So, we can have these two digit numbers , As :
we take x = 1 and y 4 , So
14 + 27 = 41
Or
we take x = 2 and y 5, So
25 + 27 = 52
Or
we take x = 3 and y 6 , So
36 + 27 = 63
Or
we take x = 4 and y 7 , So
47 + 27 = 74
Or
we take x = 5 and y 8 , So
58 + 27 = 85
Or
we take x = 6 and y 9 , So
69 + 27 = 96
So,
we can say two digit numbers ( 14 , 25 , 36 , 47 , 58 , 69 ) when added to 27 get reversed.
HOPE IT HELPS....
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