Question

which two numbers have a sum of 11 and a product of 28​

Answer 1

Answer:

7 and 4 are the numbers having sum of 11 and product of 28.

hope that it helps...

Answer 2

Answer:

Required value of two numbers are 4 and 7.

Step-by-step explanation:

Given,sum of two numbers is 11 and a product of them is 28.

Let first number be a and second number be b.

According to question,

$a + b = 11...(1) \\ ab = 28....(2)$

From equation (1),

$a + b = 11 \\ a = 11 - b....(3)$

Putting value of a in equation (2),

$(11 - b) \times b = 28 \\ 11b - {b}^{2} = 28 \\ {b}^{2} - 11b + 28 = 0 \\ {b}^{2} - (7 + 4)b + 28 = 0 \\ {b}^{2} - 7b - 4b + 28 = 0 \\ b(b - 7) - 4(b - 7) = 0 \\ (b - 7)(b - 4) = 0$

We know product of two numbers is zero then they are also separately zero.

$b - 7 = 0 \\ b = 7$

and

$b - 4 = 0 \\ b = 4$

We are putting b = 7 in equation (3),

$a = 11 - 7 \\ = 4$

and we are putting value of b = 4 in equation (3),

$a = 11 - 4 \\ = 7$

So, required value of two numbers are 4 and 7.

This is a problem of Algebra.

Know more about Algebra,

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2) https://brainly.in/question/1169549

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