Question

Which two numbers have a sum of 15and A products of 36

Answer 1

$\huge\red{\ddot\smile}$ hope it helps you ✔️ ✅$\huge\red{\ddot\smile}$

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{If\:y=12}}}$

$\green{\tt{\therefore{then\:x=3}}}$

$\green{\tt{\therefore{If\:y=3}}}$

$\green{\tt{\therefore{then\:x=12}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given: }} \\ \tt:{\implies Sum \: of \: two \: numbers = 15} \\ \\ \tt: \implies Product \: of \: two \: numbers = \\ \\ \red{\underline \bold{To \: Find: }} \\ \tt: \implies Number = ?$

• According to given question :

$\text{Let \: number \: be \: x \: and \: y} \\ \\ \bold{As \:the \:given \: relation} \\ \tt: \implies x + y = 15 - - - - - (1) \\ \\ \tt: \implies xy = 36 \\ \\ \tt: \implies x = \frac{36}{y} - - - - - (2) \\ \\ \text{Putting \: value \: of \: x \: in \: (1)} \\ \tt: \implies \frac{36}{y} + y = 15 \\ \\ \tt: \implies 36 + {y}^{2} = 15y\\ \\ \tt: \implies {y}^{2} - 15y + 36 = 0 \\ \\ \tt: \implies {y}^{2} - 12y - 3y+ 36 = 0 \\ \\ \tt: \implies y(y - 12) - 3(y - 12) = 0 \\ \\ \tt: \implies (y - 12)(y - 3) = 0 \\ \\ \green{\tt: \implies y = 12 \: and \: 3} \\ \\ \text{Putting \: value \: of \: y = 12 \: in \: (2)} \\ \tt: \implies x = \frac{36}{12} \\ \\ \green{\tt: \implies x = 3} \\ \\ \text{Putting \: value \: of \: y = 3 \: in \: (2)} \\ \tt: \implies x = \frac{36}{3} \\ \\ \green{\tt: \implies x = 12}$