Which two of the oxides (CO2, SiO, BeO, NO, ZnO) react neither with KOH nor with HCl?
Answers
No and SiO²
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Zinc oxide (ZnO), Tin(IV)oxide or SnO2, Aluminum oxide (Al2O3) and Beryllium oxide (BeO) are all amphoteric substances, meaning they can react with both acids and bases.
Zinc oxide, ZnO :
It is nearly insoluble in water, but it will dissolve in most acids, such as hydrochloric acid:
ZnO + 2 HCl → ZnCl2 + H2O
Solid zinc oxide will also dissolve in bases to give soluble zincates:
ZnO + 2 NaOH + H2O → Na2[Zn(OH)4]
Tin (IV) oxide or SnO2:
Tin oxides dissolve in acids including HI to give hexaiodostannates, [SnI6]2−.
SnO2 + 6 HI → H2SnI6 + 2 H2O
SnO2 also dissolves in sulfuric acid to give the tin sulfate:
SnO2 + 2 H2SO4→ Sn(SO4)2 + 2 H2O
SnO2 dissolves in strong base to give stannates (Na2SnO3).
SnO2 + 2NaOH → Na2SnO3 + H2O
Dissolving the solidified SnO2/NaOH melt in water gives Na2[Sn(OH)6]2.
Aluminum oxide, Al2O3 :
Aluminium oxide dissolves in acids such as hydrofluoric acid to give fluoride salt.
Al2O3+ 6 HF → 2 AlF3 + 3 H2O
Al2O3 also dissolves in strong base such as NaOH to give aluminate, NaAl(OH)4.
Al2O3 + 2 NaOH + 3 H2O → 2 NaAl(OH)4
Beryllium oxide, BeO :
Beryllium oxide reacts with acids :
BeO + 2H+ --> Be2+ + H2O
It dissolves easily in a solution of hot concentrated sulfuric acid (H2SO4).
BeO + H2SO4 --> BeSO4 + H2O
Beryllium oxide also dissolves in base.
BeO + 2OH- + H2O --> Be(OH)42-