Question

which type of arithmetic progression 5, 15, 25............. will be 130

Answer 1

Answer:

a=5,d=10

31st term =a+30d

=5+30*10=5+300

=305

Given 5,15,25…..will be 139 more than 31st term.

So add 130+31st term

=130+305=435

Now a+(n-1)d

435=5+(n-1)10

435=5+10n-10

435=-5+10n

435+5=10n

440=10n

n=440/10=44th term

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