Which value of b would make y^2+by-24 factorable
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Answer:
b is one of
2, 5, 10, 23or their negatives
Explanation :
Given quadratic is y² + by - 24 =0
We know the standard quadratic equation
ax² + bx + c = 0
Factors or roots exist if ,
b² - 4ac = perfect square
b² - 4 (1)(-24)
= b² + 96
So, b is one of
2, 5, 10, 23 or their negatives
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