Math, asked by vd32987, 2 months ago

which value of y would satisfy the equation 5y+8=3y-2?​

Answers

Answered by Anonymous
33

\large\sf\underline{Given\::}

  • \sf\:5y+8=3y-2

\large\sf\underline{To\:find\::}

  • Value of y such that the given equation is verified.

\large\sf\underline{Solution\::}

\sf\:5y+8=3y-2

  • Transposing 3y from RHS to LHS. As +ve sign lies in 3y when we transpose it the sign changes to -ve.

\sf\implies\:5y-3y+8= -2

\sf\implies\:2y+8= -2

  • Transposing 8 from LHS to RHS. As +ve sign lies in 8 when we transpose it the sign changes to -ve.

\sf\implies\:2y= -2 -8

\sf\implies\:2y= -10

  • Transposing 2 from LHS to RHS. As × sign lies between 2 and y when we transpose 2 to other side the sign changes to ÷ .

\sf\implies\:y= \cancel{\frac{-10}{2}}

\large{\underline{\boxed{\mathrm\pink{\implies\:y\:=\:-5}}}}

___________________________

\large\sf\underline{Verifying\::}

\sf\:5y+8=3y-2

  • Let's substitute the value of y as ( - 5 )

\sf\implies\:5 (-5) +8=3 (-5) -2

\sf\implies\:-25 +8= -15 -2

\sf\implies\:\cancel{-}17=\cancel{ -}17

\sf\implies\:17= 17

\small\fbox\blue{Hence\:Verified}

___________________________

!! Hope it helps !!

Answered by VεnusVεronίcα
148

\large\green { \mathscr {Q \mathfrak {uestion:-}}}

Which value of y would satisfy the equation \rm 5y+8=3y-2?

 \\

\large \green {\mathscr {S\mathfrak{olution:-}}}

\pink {\implies}\tt 5y+8=3y-2

\pink {\implies}\tt 5y-3y=-2-8

\pink \implies \tt 2y=-10

\pink \implies \tt y= \cfrac{ - 10}{2}

\underline {\boxed {\tt {\pink {\therefore y=-5 \: for \: 5y+8=3y-2}}}}

 \\

\large \green {\mathscr {V \mathfrak {erification:-}}}

Substituting y = -5 in 5y + 8 = 2y - 2 and solving :-

\pink \implies \tt 5y+8=2y-2

\pink \implies \tt 5(-5)+8=3(-5)-2

\pink \implies \tt -25+8= - 15 - 2

\pink \implies \tt -17=-17

\underline {\boxed {\tt \pink {Hence, verified \: !!}}}

 \\

____________________

Hope the answer's clear!!

Similar questions