Question

Which vertex of triangle PQR is right angled if PQ =8cm , QR=10cm and PR = 6cm?​

Answer 1

Given -

AB = 5

BC = 4

To find -

AC

Solution :-

By applying Pythagoras theorem -

➩ \sf AC^2 + BC^2 = AB^2AC

2

+BC

2

=AB

2

➩ \sf AC^2 + 4^2 = 5^2AC

2

+4

2

=5

2

➩ \sf AC^2 + 16 = 25AC

2

+16=25

➩ \sf AC^2 = 25 - 16AC

2

=25−16

➩ \sf AC^2 = 9AC

2

=9

➩ \sf AC = 3AC=3