Which what velocity dies water flow out of an drifice in a tank with gauge pressure 4y

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ρ−ρ
0
=4×10
5
Pa,ρ=10
3
If the orifice is at a depth h from the water surface in a tank, the gauge pressure there is
ρ−ρ
0
=hρg ....(1)
By Toricelli's law of efflux, the velocity of efflux,
v=
2gh
...(2)
Substituting for h from Eq.(1),
v=
2g
ρg
rho−ρ
0
=
2
ρ
ρ−ρ
0
=
10
3
2(4×10
5
)
=20
2
=28.28m/s.
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