Which will form more number of moles than 34g of ammonia?
18g of H2O
132g of CO2
10g of H2
80g of 02
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Answer:
«» 34 g of ammonia (NH3)
Number of moles = Given mass /molar mass
= 34/(14+1*3)
= 34/17
= 2 moles
«» 18 g of H20
Use the same Formula
18 / 1*2 + 16
= 18/18
= 1 mole
«» 132 g of CO2
132/12 + 16*2
132/44
= 3 moles
«» 80g of O2
80/16*2
80/32
= 2.5 moles
132g of CO2 and 80g of O2 both will form more number of moles than 34g of ammonia. 132g of CO2 forms the highest number of moles, i.e.,3 moles.
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