Physics, asked by jiteshsingh11137, 8 months ago

Which would require a greater force-accelerating a 3 kg mass at 5m/s2 or a 4 kg mass at 4 m/s2?

Answers

Answered by BrainlyRaaz
43

First case:

Mass, m = 3 kg

Acceleration,  5 \ \mathrm{m} / \mathrm  {s}^{2}

Second case:

Mass, m = 4 kg

Acceleration,  4 \ \mathrm{m} / \mathrm  {s}^{2}

Solution:

The force is measured product of mass and acceleration so the force is directly dependent upon the mass of the body as well as the acceleration. So, the greater force required is compared by calculating force on each as follows,

 \text{Force} = \text{Mass} \times \text{Acceleration}

 \text{Force} =\mathrm{m} \times \mathrm{a}

For the first case,

 \mathrm{F}= 3 \times 5

 F = 15N

For the second case,

 \mathrm{F}=4 \times 4

 F = 16 N

So, the first case has greater force required than the second case.

Answered by InsaneBanda
1

\huge{\underline{\underline {\mathtt{\purple{ą}\pink{ŋ}\green{ʂ}\blue{ῳ}\red{ɛ}\orange{ཞ}}}}}

First case:

Mass, m = 3 kg

Acceleration, 5m/s²

Second case:

Mass, m = 4 kg

Acceleration, 4m/s²

Solution:

The force is measured product of mass and acceleration so the force is directly dependent upon the mass of the body as well as the acceleration. So, the greater force required is compared by calculating force on each as follows,

Force=Mass×Acceleration

Force=m×a

For the first case,

F = 3×5

F = 15NF=15N

For the second case,

F= 4×4

F = 16 NF=16N

So, the first case has greater force required than the second case.

~Answer completed~⁣

~Be Brainly ~⁣ :)

Similar questions