Chemistry, asked by alkatanuyadav, 11 months ago

Which would undergoes sn2 reaction faster c6h5-ch2-ch2-br and c6h5-ch-ch3-br

Answers

Answered by rockayush68
3

Answer:

c6h5-ch2-ch2- br is react faster

rate of SN2 inversely proportional to steric hindrance

Answered by gautamrawatlm
3

Answer:

\[{C_6}{H_6} - C{H_2} - C{H_2} - Br\] will undergo a fast \[{S_N}^2\] reaction also known as a second-order substitution reaction.

Explanation:

In the case of second-order substitution reaction(\[{S_N}^2\]) nucleophile attacks in 1° carbon fast because of less steric hindrance.

The order of second-order substitution reaction (\[{S_N}^2\]) is :

1°>2°>3° carbons.

The reason behind this is, that at 3° carbon there is a lot of steric hindrance due to which reaction gets slow.

At 2° carbon steric hindrance reduces and the reaction gets fast.

At 1° carbon, there is the least steric hindrance and the reaction is fastest.

Therefore,  In \[{C_6}{H_6} - C{H_2} - C{H_2} - Br\] Br is connected at 1° carbon and \[{S_N}^2\] will be the fastest.

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