Question

Which would weigh more, 10 moles of CH, or 2 moles of C2H5OH?​

Answer 1

Moles of any compound can be defined as the given weight of the compound divided by the molecular weight of the compound.

Explanation:

To decide which compound weighs more by the moles given we first calculate the weight using the formula: -

$Moles = \frac{Weight of Compound (w)}{ Molecular weight of compound (M)}$

To calculate the weight of 10 moles of CH; we first calculate the molecular weight of CH.

$Molecular weight of CH = Molecular weight of C + Molecular weight of H$

$Molecular weight of CH = 12 + 1$

$Molecular weight of CH = 13$

Now, weight of CH can be calculated by $Moles = \frac{Weight of Compound (w)}{ Molecular weight of compound (M)}$

Substituting:

$10 = \frac{Weight of CH}{13}$

$Weight of CH = 13* 10$

$Weight of CH = 130 grams$

Similarly, we need to calculate the weight of 2 moles of C2H5OH; we first calculate the molecular weight of C2H5OH.

$Molecular weight of C2H5OH = 2*(Molecular weight of C) +6*( Molecular weight of H) + Molecular weight of O$$Molecular weight of C2H5OH = 2*(12) +6*( 1) + 16$

$Molecular weight of C2H5OH = 24 +6+ 16\\Molecular weight of C2H5OH = 46$

Now, weight of C2H5OH can be calculated by $Moles = \frac{Weight of Compound (w)}{ Molecular weight of compound (M)}$

Substituting:

$2 = \frac{Weight of Compound (w)}{ 46}\\Weight of C2H5OH = 46*2\\Weight of C2H5OH = 92 grams$

Comparing the calculating weights of CH and C2H5OH

CH = 130 grams

C2H5OH = 92 grams

Hence 10 moles of CH weighs more than 2 moles of C2H5OH.