While approaching a cliff in a car, a man fires a gun from a distance of 0.335 km. If the velocity of the car is 5m/s. When and where will the echo be heard by the man? (Take velocity of sound as 330m/s)
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Answer:
2.5 sec here a echo at 3 sec
Explanation:
Let the distance of the cliff from the initial position of the man be d m.
So, the distance traveled by sound in 3 sec=2d m
So, speed of sound, S=
Time
Distance
S=
3
2d
.....(i)
On moving closer to the cliff by a distance of 82.5 m, the distance=2(d−82.5) m
So,
S=
t
d
S=
2.5
2(d−82.5)
=
2.5
2d−2×82.5
.....(ii)
Therefore form equation (i) and (ii)
3
2d
=
2.5
2d−2×82.5
5d=6d−495
d=495 m
Thus it is the distance of the cliff from the initial position of the man.
Now,
S=
3
2×495
=330 m/s
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