Math, asked by NineTaliedFox, 11 months ago

While boarding a plane, a passenger got hurt. The pilot

showing promptness and concern, made arrangements to

hospitalize the injured and so the plane started late by 30

minutes to reach destination, 1500km away in time, the pilot

increased the speed by 10km/h. Find the speed of the plane.​

Answers

Answered by Anonymous
8

Answer:

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Step-by-step explanation:

Let the Original speed of the aeroplane be x km/h.

Time taken to cover 1500 km with the usual speed of x km/h = 1500 / x hrs

Time taken to cover 1500 km with the increase speed of (x+100) km/h = 1500 / (x+100) hrs

ATQ

1500 / x = 1500 / (x+100) + ½

1500 / x -  1500 / (x+100) = ½

1500(x+100) -1500x / x(x+100)= ½

1500x + 1500 × 100 -1500x / x² +100x = ½

1500 × 100 / x² +100x = ½

2(1500 × 100 ) = x² + 100x

300000 = x² +100x

x² +100x - 300000 =0

x² -  500 x  + 600 x - 300000= 0

x(x - 500) + 600(x - 500)= 0

(x+600)  (x - 500) = 0

(x+600)  = 0  or  (x - 500) = 0

x = -600  or  x = 500

Speed cannot be negative, so x = 500

Hence,  the usual speed of the plane is 500 km/h.

The value depicted by the pilot here are humanity.

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