While boarding a plane, a passenger got hurt. The pilot
showing promptness and concern, made arrangements to
hospitalize the injured and so the plane started late by 30
minutes to reach destination, 1500km away in time, the pilot
increased the speed by 10km/h. Find the speed of the plane.
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Answer:
Step-by-step explanation:
Let the Original speed of the aeroplane be x km/h.
Time taken to cover 1500 km with the usual speed of x km/h = 1500 / x hrs
Time taken to cover 1500 km with the increase speed of (x+100) km/h = 1500 / (x+100) hrs
ATQ
1500 / x = 1500 / (x+100) + ½
1500 / x - 1500 / (x+100) = ½
1500(x+100) -1500x / x(x+100)= ½
1500x + 1500 × 100 -1500x / x² +100x = ½
1500 × 100 / x² +100x = ½
2(1500 × 100 ) = x² + 100x
300000 = x² +100x
x² +100x - 300000 =0
x² - 500 x + 600 x - 300000= 0
x(x - 500) + 600(x - 500)= 0
(x+600) (x - 500) = 0
(x+600) = 0 or (x - 500) = 0
x = -600 or x = 500
Speed cannot be negative, so x = 500
Hence, the usual speed of the plane is 500 km/h.
The value depicted by the pilot here are humanity.
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