Question

while calculating average of 5 no's, astudentbwrote one no as 54 instead of 45 by mistake. as result he got the average as 52. the correct average of the numbers is ​

Answer 1

Answer:

Step-by-step explanation:et five no be a, b, c, d and54.

So a+b+c+d+54 equals to 52*5 equals to 260

Now subtract 54 from 260 and add 45

That is 260-54+45=251

Now 251/5= 50.2

So 50.2 is correct answer

Answer 2

The corrected average is 50.2

Given:

While calculating average of 5 No.'s of students one observation has written as 54 instead of 45

And they got average as 52

To find:

The correct average of the numbers

Solution:

Given that average of 5 No.'s = 52

As we know average = sum of number/number of observations

⇒ sum of numbers / 5 = 52

⇒ Sum of numbers = 52×5 = 260

⇒ Sum of numbers = 260

Here 54 is written instead of 45

⇒ Subtract 54 and add 45 to the sum of the numbers

⇒ 260 - 54 + 45 = 251  is correct sum of the numbers

⇒ Average of 5 No.'s = 251/5 = 50.2  

The corrected average is 50.2

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