while calculating average of 5 no's, astudentbwrote one no as 54 instead of 45 by mistake. as result he got the average as 52. the correct average of the numbers is
Answers
Answer:
Step-by-step explanation:et five no be a, b, c, d and54.
So a+b+c+d+54 equals to 52*5 equals to 260
Now subtract 54 from 260 and add 45
That is 260-54+45=251
Now 251/5= 50.2
So 50.2 is correct answer
The corrected average is 50.2
Given:
While calculating average of 5 No.'s of students one observation has written as 54 instead of 45
And they got average as 52
To find:
The correct average of the numbers
Solution:
Given that average of 5 No.'s = 52
As we know average = sum of number/number of observations
⇒ sum of numbers / 5 = 52
⇒ Sum of numbers = 52×5 = 260
⇒ Sum of numbers = 260
Here 54 is written instead of 45
⇒ Subtract 54 and add 45 to the sum of the numbers
⇒ 260 - 54 + 45 = 251 is correct sum of the numbers
⇒ Average of 5 No.'s = 251/5 = 50.2
The corrected average is 50.2
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