Question

While calculating the average of first few natural numbers?

Answer 1

Let you have to calculate the average of first 'n' natural numbers.
As the sum of first n natural numbers is given as Sn = n(n+1)/2
Now average of any numbers is : Sum of numbers÷Total no. of numbers
= (Sn)/n
= (n(n+1)/2)/n
= (n+1)/2

Thus average of first 'n' natural numbers is (n+1)/2

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Answer 2

n(n+1)/2*1/n=(n+1)/2