Question

while calculating the e/m ratio which gas used by Thomson​

Answer 1

Answer:

hydrogen gas

Explanation:

For better results in a cathode tube experiment, an evacuated (low pressure) tube is filled with hydrogen gas that is the lightest gas (maybe the lightest element) on ionization, giving the maximum charge value to the mass ratio (e / m ratio = 1.76 x 10 ^ 11 coulombs per kg).

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