while cycling along the wind a boy can cover a distance of 30 km in 3 hours and returning back through the same distance he takes 5 hours find the speed of wind and the speed of cycling in still air
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let the speed of cycling in still air is x
speed of wind = y
now cycling along the wind
30/(x+y) = 3
x+y = 10 --------(1)
opposite wind
30/(x-y) = 5
x-y = 6 ---------(2)
solving 2 equations we get
x = 8
y = 2
so the speed in still air is 8kmph
and speed of wind is 2kmph
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