While cycling along the wind; A boy can cover distance of 30 km in 3 hours and for returning back through the same distance he takes 5 hours. Find the speed of wind and the speed of cycling in air.
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Answered by
65
According to question
Let speed of Cyclic in Still Air be u
and Speed of Air be v
Thus,
While cycling long the wind
Speed = v+ u
and given that x = 30 Km
when t = 3 hrs
So, v+ u = 30/t
v + u = 30 / 3 = 10
So v + u = 10
Similarly
while cycling in opposite direction
Speed = v - u
So
v - u = 30/5
v - u = 6
Thus equating the above two equations
2v = 16
v = 8
So u = 2
Let speed of Cyclic in Still Air be u
and Speed of Air be v
Thus,
While cycling long the wind
Speed = v+ u
and given that x = 30 Km
when t = 3 hrs
So, v+ u = 30/t
v + u = 30 / 3 = 10
So v + u = 10
Similarly
while cycling in opposite direction
Speed = v - u
So
v - u = 30/5
v - u = 6
Thus equating the above two equations
2v = 16
v = 8
So u = 2
Answered by
1
Answer:
HOPE IT HELPS
Step-by-step explanation:
so here I have taken speed of wind as x and speed of cycle as y but you can take it either wind as y or cycle as x............. It won't be wrong
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