While determining the density of the material of a sphere, using a spring balance and measuring cylinder, a
student noted the following readings : [1]
(i) Mass of the sphere = 81 g
(ii) Reading of water level in the cylinder without sphere in it = 54 ml
(iii) Reading of water level in the cylinder with sphere in it = 63 ml
On the basis of these observations, the density of the material of the sphere is
(a) 1500 kg/m3
(b) 6000 kg/m3
(c) 7000 kg/m3
(d) 9000 kg/m3
Answers
Answered by
113
Hey there !
Mass = 81 grams = 0.008 kg
Initial reading = 54 ml
Final reading = 63 ml
Volume of sphere = Amount of water displaced by it
Amount of water displaced by it =
Final reading - Initial reading
= 63 - 54
= 9ml
Volume = 9 ml = 9 cm³ [ 1 ml = 1 cm³]
Density = Mass / Volume
= 81/9
= 9 g/cm³
= 9000 kg/m³ [1g/cm³ = 1000 kg/m³]
Hence option (D) is correct !!
Hope this helps you !
Mass = 81 grams = 0.008 kg
Initial reading = 54 ml
Final reading = 63 ml
Volume of sphere = Amount of water displaced by it
Amount of water displaced by it =
Final reading - Initial reading
= 63 - 54
= 9ml
Volume = 9 ml = 9 cm³ [ 1 ml = 1 cm³]
Density = Mass / Volume
= 81/9
= 9 g/cm³
= 9000 kg/m³ [1g/cm³ = 1000 kg/m³]
Hence option (D) is correct !!
Hope this helps you !
Answered by
41
Volume of sphere= water displaced by it
Water displaced by it= final water level- initial water level
= 63-54
=9ml
= 9cm3
density= Mass/ volume
density= 81g/9cm3
= 9g/cm3
=9000kg/m3
therefore d part is the right answer.
hope this helps you...
pl mark it as a brainliest answer...
Water displaced by it= final water level- initial water level
= 63-54
=9ml
= 9cm3
density= Mass/ volume
density= 81g/9cm3
= 9g/cm3
=9000kg/m3
therefore d part is the right answer.
hope this helps you...
pl mark it as a brainliest answer...
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