Question

while doing an experiment with concave mirror,Anand identified size of an image equal to the size of object
1. where the object is placed?
2. what is the magnification value at this position?
3. Draw the ray diagram for it?​

Answer 1

When the object is placed at the centre of curvature, the image formed is of the same size.

Magnfication is the height of the image / height of the object. And since they are of the same size and hence same height., the magnification is equal to 1