while driving his car at a speed of 50 km/ hr, ramit cover a distance from home to his office in 1 hour 30 min. One day he was 15 min late from his home. In order to reach office at time, what should be the speed of the car???
From chapter - direct and inverse variation...
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Answers
Answered by
24
distance from home to office is= 50×1.5hr=75km
as car is moving with a speed of 50km/hr and it take 1hr 30min(1.5hr) to reach office
so now time left with him is =(90-15)min=75min=1.25 hr
so speed of the car must be=75/1.25=7500/125=60km/hr
as car is moving with a speed of 50km/hr and it take 1hr 30min(1.5hr) to reach office
so now time left with him is =(90-15)min=75min=1.25 hr
so speed of the car must be=75/1.25=7500/125=60km/hr
Answered by
5
Answer:
speed = distance/time
given,
speed=50km/he
time taken=1.5hr
distance=x
50=x/1.5
x=75 km
if he was 15 mins late he should cover 75 km in 1hr15mins=1.25hr
=75/1.25
=60 km/hr
Total distance covered by him =speed = distance/time
given,
speed=50km/he
time taken=1.5hr
distance=x
50=x/1.5
x=75 km
if he was 15 mins late he should cover 75 km in 1hr15mins=1.25hr
=75/1.25
=60 km/hr
Total distance covered by him daily=75+75=150km
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