Question

while finding the average of 10 given numbers a student by mistake write 64 in place a number of 46 and got his average 50, the correct average of the given number was.​

Answer 1

Answer:

Average=48.2

Step-by-step explanation:

Consider 10 nos a1.. . a10

Let a10=wrong number=64

So (a1+a2+... .. +a9+64)/10=50

On solving

a1+a2+... .. +a9=436

Now a10=correct no=46

So average,

(a1+a2+... .. . +a9+46) /10=(436+46) /10=482/10=48.2

Answer 2

The correct average of the given number was 48.2

Step-by-step explanation:

Mean of 10 number is 50

$Average = \frac{\text{Sum of observations}}{\text{No. of observations}}$

$50 =\frac{\text{Sum of 10 numbers}}{10}\\50 \times 10 = \text{Sum of 10 numbers}\\500 = \text{Sum of 10 numbers}$

a student by mistake write 64 in place a number of 46

So, New sum = 500-64+46=482

So New average = $\frac{482}{10}=48.2$

Hence The correct average of the given number was 48.2

#Learn more:

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