while going to college student's average speed for this trip is 20kmph on his return trip along the same route average speed is 40kmph. what is average speed for this trip?
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avg speed = total distance÷ total time taken
case 1.
let dis =x
speed=20
so time1=x/20
case2.
time2=x/40
Total time=(x/20)+(x/40)=3x/40
avg speed= (dis1+dis2)/total time
(2x)/(3x/40)
=
= 80/3 kmph
case 1.
let dis =x
speed=20
so time1=x/20
case2.
time2=x/40
Total time=(x/20)+(x/40)=3x/40
avg speed= (dis1+dis2)/total time
(2x)/(3x/40)
=
= 80/3 kmph
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