While landing at an airport, a pilot made an angle of depression of 20°. Average speed of the plane was 200 km/hr. The plane reached the ground after 54 seconds. Find the height at which the plane was when it started landing. (sin 20° = 0.342)
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Answer:
the height of the plane is 1.026 km
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Step-by-step explanation:
A is rhe starting place of landing
AD is a horizontal line and AC is a
Line of vision which makes an angle of
DAC =20°
Angle DAC=AngleBCA=20° (alternate angle test)
Speed=200km/hr=2000km) =200×1000m
1hr 3600sec
Distance=speed ×time
20000×54
3600
Distance AC=3000m
In right angle triangle ABC
Sin20=opposite/hypotenuse
0.342=AB/3000
342×3000=AB (decimal remove)
100
AB =1026m
Km=1026/1000
1.026km
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