Question

while landing at an airport, a pilot made an angle of depression of 20°. Average
speed of the plane was 200 km/hr. The plane reached the ground after 54 seconds.
Find the height at which the plane was when it started landing. (sin 20º = 0.342)​

Answer 1

Answer:

$\: \: \: \: \: \:$

the height at which the plane was when it started landing = 1.026 km

Step-by-step explanation:

While landing at an airport, a pilot made an angle of depression of 20°. Average speed of the plane was 200 km/hr. The plane reached the ground after 54 seconds.

Distance = Speed * time

Distance traveled by plane = 200 *  54/3600   ( 54 sec = 54/3600 hr)

=  3km

Sinθ = perpendicular /hypotenuse

Angle of depression = angle of elevation

Sin20° = Height of Plane when it started landing /Distance Travelled by plane

=> 0.342 = Height of plane when it started landing / 3

=>  Height of plane when it started landing = 3 * 0.342 = 1.026 km