While launching a rocket of mass of 20000kg a force of 500000newton is applied for 20 s .calculate the velocity obtained by the rocket at the end of 20sec?
Answers
Answered by
58
F = m * (v-u)/t
u = 0
F = mv/t
v = Ft/m
v = 5 * 10^5 * 20 / (2 * 10^4)
v = 500 m/s
Velocty at the end of 20s is 500m/s
u = 0
F = mv/t
v = Ft/m
v = 5 * 10^5 * 20 / (2 * 10^4)
v = 500 m/s
Velocty at the end of 20s is 500m/s
Answered by
54
F=ma
5×10^5 N = (2×10⁴) × a
500000/20000= a
25 m/s² = a
using first equation of motion
v=u+at
v=0 +25(20)
v= 500m/s
hope this helps
5×10^5 N = (2×10⁴) × a
500000/20000= a
25 m/s² = a
using first equation of motion
v=u+at
v=0 +25(20)
v= 500m/s
hope this helps
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