While making his peg, an unconscious drunkard filled his glass of 100 ml completely with water. He took a sip of 20 ml from the glass and consequently, realised his mistake. So he added 10 ml of alcohol to it. He took a sip of 20 ml again, and added 10 ml of alcohol thereafter. He kept on doing this until his glass became empty.What is the net quantity of alcohol that the drunkard sipped till his glass became empty?
Answers
Answer:
80ml
Step-by-step explanation:
- 100 ml-----80ml
- 80+10ml=90ml----------70ml
- 70+10ml=80ml----------60ml
- 60+10ml=70ml----------50ml
- 50+10ml=60ml---------40ml
- 40+10ml=50ml----------30ml
- 30+10ml=40ml----------20ml
- 20+10ml=30ml----------10ml
- 10+10ml=20ml-----------0ml
In this way he slipped 80ml of alcohol
The Net Quantity Of Alcohol Sipped Is 80ml
GIVEN
The initial volume of water = 100ml
Quantity of glass he sipped = 20 ml
Subsequent addition of alcohol = 10 ml
TO FIND
Final Quantity of alcohol the drunkard sipped.
SOLUTION
We can simply solve the above problem as follows-
The quantity of alcohol the drunk sipped will be equal to the volume of alcohol added to the solution.
Let the volume of alcohol added to the glass be, T1, T2......
According to the question -
The initial quantity of water, V = 100 ml
Amount of water sipped = 20 ml
New solution V1 = 100-20 = 80
The volume of Addition of alcohol (T1) = 10ml
New solution (v2) = 80 +10 = 90ml
Amount of solution sipped = 90-20 = 70ml
The volume of alcohol added (T2) = 10 ml
New volume (v3) = 70+10 = 80 ml
The volume of solution sipped = 20ml
New volume = 80-20 = 60ml
The volume of alcohol added (T3) = 10 ml
New volume = 60+10 = 70 ml
The volume of solution. after sipping 20 ml = 70-20=50ml
The volume of alcohol added(T4) = 10ml
New solution = 50+10 = 60ml
The volume of solution after sipping 20 ml = 60-20 = 40ml
Volume. of alcohol added (T5) = 40+10= 50 ml
the volume of solution after sipping 20 ml = 50-20 = 30 ml
The volume of alcohol added (T6) = 10 ml
New volume = 30+10 = 40 ml
Volume after sipping 20 ml = 40-20 = 20ml
The volume of alcohol added (T7) = 10 ml
New volume = 20+10= 30ml
The volume of solution after sipping 20 ml = 30-20 = 10ml
The volume of alcohol added (T8) = 10ml.
New volume = 10+10 = 20ml.
The volume of solution after sipping 20ml = 0
So, Quantity of alcohol = T1 +T2+T3 + T4 + T5 + T6 = 80 ml
Hence, The Net Quantity Of Alcohol Sipped Is 80ml
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