Question

: While measuring the acceleration due to gravity by a simple pendulum, a
student makes a positive error of 1% in the length of the pendulum and a
negative error of 3% in the value of time period. His percentage error in
the measurement of g by the relation g =
$47\pi {}^{2} ( \frac{1}{t {}^{2} } )$


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Answer 1

I am Jiya bhabad OK got it