While measuring the side of a square an error of 7% in excess is made what is percentage error in area of square?
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A = L^2 area of square
A + dA = (L + .07 L)^2 where dA is error in A due to error in L
A + dA = L^2 * (1 + .07)^2 = L^2 * ( 1 + .14 + .0049) = 1.14 = L^2 + 2 *L *dL
(the term .0049 is usually omitted because it is small)
A + dA - A = L^2 + 2 L dL - L^2
or dA = 2 L dL = .14 L where dA and dL are the errors involved
dA / A = 2 L dL / L^2 = 2 dl / L = 2 * 7% = 14 % where dL / L is fractional error in L
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