While multiplying two numbers a student who reversed the digits of any one number got the answer 391 . Later he realised that the product must be even . Find the sum of all prime divisors of the correct product.
Answers
Answer:
256
Step-by-step explanation:
hope it helps
Given : While multiplying two numbers a student who reversed the digits of any one number got the answer 391 .
Later he realized that the product must be even .
To Find : the sum of all prime divisors of the correct product.
Solution:
391 = 17 * 23
reversed the digits of any one number
Hence it could be
71 * 23 or 17 * 32
71 * 23 = Odd
17 * 32 = even
the product must be even
Hence it must be 17 * 32
17 * 32 = 2 * 2 * 2 * 2 * 2 * 17
Sum of all prime divisors
2 + 2 + 2 + 2 + 2 + 17
= 27
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