Question

While performing qualitative analysis one candidate heated the frozen mixture at -23 °C to a very high temperature, thus using a pyrometer, he found the temperature of the flask was 477 °C. What fraction of air would have been expelled out
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Answer 1

Answer:

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Answer 2

Explanation:

Given While performing qualitative analysis one candidate heated the frozen mixture at -23 °C to a very high temperature, thus using a pyrometer, he found the temperature of the flask was 477 °C. What fraction of air would have been expelled out

• So initial temperature T1 = - 23 degree C
•                                           = 273 - 23
•                                           = 250 K
• So the final temperature T2 = 477 degree C
•                                                 = 273 + 477
•                                                 = 750 K
• So pressure and volume is constant  
• Now pv = constant.
• Therefore n1T1 = n2T2
• So it is not an isothermal process.
• So n2 / n1 = T1 / T2
•                = 250 / 750
•            = 1/3
• So fraction of moles of air expelled out will be  
•                                        1 – n2 / n1
•                                     = 1 – 1/3
•                                    = 2/3

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