While performing the experiment with raisins to determine the percentage of water absorbed by them, a student made following measurements: 1; Mass of water in the beaker = 40 g; Mass of raisins before soaking = 5 g; Mass of raisins after soaking or 2 hours = 8 g; Mass of water left in the beaker after the experiment = 35 g; The percentage of water absorbed by raisins is:; A.; B.; C.; D.(Delhi - 2012)
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Answer:
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Explanation:
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While performing the experiment with raisins to determine the percentage of water absorbed by them, the percentage of water absorbed by raisins is 60%
1. Let us assume the initial weight of water to be W1, initial weight of raisins to be w1, final weight of water to be W2 and final weight of raisins to be w2.
2. Then, the percentage of water absorbed by raisins = ((change in weight of raisins)/ (change in weight of water)) ×100
=((w2-w1)/(W2-W1))×100
=((8-5)/(40-35))×100 = 60%