Question

While performing the experiment with raisins to determine the percentage of water absorbed by them, a student made following measurements:Mass of water in the beaker = 40 gMass of raisins before soaking = 5 gMass of raisins after soaking for 2 hours = 8 gMass of water left in the beaker after the experiment = 35 gThe percentage of water absorbed by raisins is:(A) (B) (C) (D)

Answer 1

The percentage of water absorbed by raisins is calculated by using the formula
W2 – W1/W1× 100.
where, W2 is the weight of wet resin and W1 is the weight of dry resin.

I cannot see the options but i have explained how to calculate it.