Question

while taking approximations in dual nature of light. How we get 12375 from hc (planck's constant x speee of light? Because from what I've calculated, it comes out to be around 20 something..​

Answer 1

Answer:

h

Explanation:

Answer 2

Explanation:

(h)=

[T

−1

]

[ML

2

T

−2

]

=[LT

−1

]

for mass, let M=C

a

h

b

G

c

[ML

0

T

0

]=[LT

−1

]

a

[ML

2

T

−1

]

b

[M

−1

L

3

T

−2

]

c

Using the principle,

b−c=1⟶(1)

a+2b+3c=0⟶(2)

−a−b−2c=0⟶(3)

So, a=

2

−1

also a=

2

1

Hence, M=C

1/2

h

1/2

G

−1/2

⇒M=

G

Ch

Similarly, for length L=

C

3

hG

and T=

C

5

hG

∴ Plank's length =

C

3

Gh

; Plank's time =

C

5

Gh

and Plank's Mass =

G

Ch

Hence, (a), (b), (d) are correct options.

hope it helps