Question

While verifying the law of conservation of mass, a student added 5 g of sodium bicarbonate to a test tube containing 14.5 g of acetic acid. The total mass of the reactant is 19.5 g but the mass of the product after the reaction is only 16.2 g. The reduction in the mass of the product is due to a) Elimination of CO2 gas b) Elimination of O2 gas c) Liberation of heat d) Elimination of CO gas

Answer 1

Answer:

elimination of co2 gass

Explanation:

BaCO3 + 2 CH3COOH → (CH3COO)2Ba + CO2 + H2O.

Answer 2

a) The reduction in the mass of the product is due to the Elimination of $CO_2$ gas

Explanation:

In the given reaction:

• Reactants are sodium bicarbonate $(NaHCO_3)$and acetic acid$( CH_3COOH)$.
• When the two substances react, the products formed are sodium acetate $( CH_3COONa)$, carbon dioxide gas$(CO_2)$, and water$(H_2O)$.

The same can be represented by the below chemical equation:

$NaHCO_3 (s) + CH_3COOH(aq) \rightarrow CH_3COONa(aq) + CO_2(g) + H_2O(l)$

Since, in the reaction, there is an evolution of carbon dioxide gas, thus, the loss in the mass of the products is due to the elimination of this gas.