Question

While working on a physics project at school physics lab, you require a 4microF capacitor in a circuit across a PD of 1kV. Unfortunately 4microF are not there but you have 2microF which can withstand a PD of 400 V are available plenty. If you decide to use the 2microF capacitors, min. no. of capacitors required are...

Answer 1

Answer:

18

Explanation:

4μF capacitor in a circuit across a PD of 1kV

2μF which can withstand a PD of 400 V

to have PD ≥ 1000

we need 3 capacitors in series  ( 3 * 400 = 1200 V = 1.2 kV > 1 kV)

Capacitance of  3 capacitors of 2μF in Series = 2/3 μF

Now to have capacitance of 4μF

We need to add 3 capacitors in parallel  4/(2/3)   = 12/2 = 6 times

So total capacitors required = 3 * 6 = 18

min. no. of capacitors required are 18