Question

Whilst working, a necklace broke. A row of pearls mislaid. One-sixth fell to the floor. One-fifth upon the bed. The young woman saved One-third of them. One-tenth was caught by her mother. If six pearls remained upon the string. How many pearls were there altogether?

Answer 1

Let the total numbers of pulse be x
So,one-sixth will be 1/6 of x= 1/6x,one-fifth=1/5x,one-third=1/3x,one tenth=1/10x
Then
1/6x+1/5x+1/3x+1/10x+6/1=x
5x+6x+10x+3x+90/30=x
24x+90/30=x
24x+90=30x
30x-24x=90
6x=90
x=90/6
x=15

Answer 2

Answer:30

Step-by-step explanation:

Let the total numbers of pulse be x

So fell on floor = 1/6x

fell on bed =1/5x

young man saved =1/3x

her mother caught =1/10x

remained in string =6

then total no. of pearls

$\frac{1}{6}*x+\frac{1}{5}*x+\frac{1}{3}*x+\frac{1}{10}*x+6=x\\\\\frac{5x+6x+10x+3x+180}{30}=x\\\\24x+180=30x\\\\6x=180\\\\x=30$

so there were total 30 pearls altogether.