Question

whire sack 2 1/2kg
brown sack 3 3/4kg
black sack 4 2/5kg
eight black sacks are lying in a factory storage unit.Rats have contaminated an average of 2/7 of wheat in each sack .How much wheat (in kg) from these sacks is still not contaminated.​

Answer 1

Answer:

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Answer 2

Solution :-

given that,

• weight of each black sack = 4(2/5) kg = (22/5) kg.
• Total sacks in factory storage = 8 black sacks .
• Rats contaminated = (2/7) of each sack.

so,

→ wheat contaminated from each black sack = (2/7) of (22/5) = (44/35)

then,

→ wheat contaminated from 8 black sack = 8 * (44/35) = (352/35) kg .

now,

→ Total weights of 8 black sacks = 8 * (22/5) = (176/5) kg .

therefore,

→ Sacks still not contaminated = (176/5) - (352/35) = (176*7 - 352) / 35 = (1232 - 352) / 35 = (880/35) = (176/7) = 25(1/7) kg. (Ans.)

Learn more :-

Shakuntla Devi, Karl Gauss, Archimedes could do a lot of quick maths since their young ages.

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